Thread: question about array and pointer

Code:

char* sche  = "Sep 29, 19:34";

Code:

char  sche[]  = "Sep 29, 19:34";

I would like to ask that 2 lines of codes above are the same meaning in C.What is the meaning of the first code and the second code
Thanks

The first is a pointer to a string literal while the second is a 14 element array of char.
In the first case the contents of the string literal cannot be altered; in the second case the contents of sche[] can be modified.

And in the first occassion you can assign pointer "sche" to something else, while in the second you cannot assign "sche" to something else

If I declare

Code:

char* sche  = "Sep 29, 19:34";

Then I can extract each char from "sche" by iterating through "sche.However if I try to use strtok() on schelike following

Code:

char delim[] = "-";
char* token1;
token1 = strtok(input,delim);
printf("token1%s\n",token1);

The compiler complains

Code:

red 322 % new.out
Segmentation fault
red 323 %

I need some help to understand this problem. Can someone give me an answer for this.
Thanks

the first one used as a initial expression of string,not just a pointer,which means it can't be use if not give it the space with malloc or somewhat else when you using it not as a initial expression.
the 2th shows sche is a array,it can be as large as you give to it after the = operator