Thread: pyramid char..

hey,, I have new problem.. hehehe..
how can we make a pyramid by using char?

eq
w
qwe
aqwer

I only can make a triangle..

Code:

#include<stdio.h>
#include<string.h>

void stringkiri(char st[], int n, char strhasil[]);

int main()
{
int i, panjangst;
char st[]="testing";
char sthasil[10];
panjangst= strlen(st);

for(i=0; i<panjangst;i++)
{
stringkiri(st,panjangst-i,sthasil);
puts(sthasil);
}
getchar();
}

void stringkiri(char st[],int n,char strhasil[])
{
int i;
for(i=0;i<n;i++)
	{
		
		strhasil[i]=st[i];
			
	}
	strhasil[i]='\0';
}

Each row of the square has the same length. You will print spaces as needed, before you print the other letters.

Each row, you print one fewer space char's ( ' ' ), before you start printing letters for that row. Which means in your loop, you're going to decrement the number of spaces, as you decrement the loop counter. Your counter should start with the one less than the center column of the first row.

yeah,, I know the theory,, but I can make it into code in C.. T_T
I can make it, if the variable is int.. but I am not sure too...

Before you can do this pyramid, you have to know how many rows the pyramid will require. For each row, you need one more space. (I used *'s here for easy counting).

You were on the right track with using strlen().

Code:

#include <stdio.h>
#include <string.h>

int main() {
  int i, j, k, row, maxCol, maxRow;
  char *letters = {"abcdefghijklmnopqrstuvwxy"};
  maxCol = strlen(letters);

  /*this was the toughest part. You can't print up the pyramid right,
  unless you know how many rows it will contain, before you start
  */
  for(i = 1, j = 1; j < maxCol; i++)
    j = (2*j + 2) ;

  //if you use postfix increment (i++), you need to subtract 1
  //to get the goal index you want, frequently.
  maxRow = i-1;

  j = k = 0;
  printf("\n\n\n");
  for(row = 0; k < maxCol; row++) {  //handles the rows
    for(i = j; i < maxRow; i++) {           
      printf("%c", '*');                         //the star's
    }
    
    for(i = 0; i <= row+j; k++, i++) { //the letters
      printf("%c", *letters+k);
    }
    putchar('\n');
    j++;
    
  }

  printf("\n\n\t\t\t     press enter when ready");
  i = getchar();
  return 0;
}
/*
****a
***bcd
**efghi
*jklmnop
qrstuvwxy
*/