Thread: output misunderstanding

I'm having trouble understanding the output of this code:

Code:

#include <stdio.h>

void a(int num);
void b(int num);

int main() {
     a(6);
     return 0;
}

void a(int num) {
     int index;
     for (index=0; index<num; index++)
          b(index);
}
void b(int num) {
     int index=0;
     for (index=0; index<num; index++)
          printf("%d", index);
}

Why is it 0012012012301234?
Why is b(0) and b(1) not taken to the account?

Originally Posted by Neotriz

I'm having trouble understanding the output of this code:

Code:

#include <stdio.h>

void a(int num);
void b(int num);

int main() {
     a(6);
     return 0;
}

void a(int num) {
     int index;
     for (index=0; index<num; index++)
          b(index);
}
void b(int num) {
     int index=0;
     for (index=0; index<num; index++)
          printf("%d", index);
}

Why is it 0012012012301234?
Why is b(0) and b(1) not taken to the account?

It's impossible to answer the question "why is the output 0012012012301234", because the output is not "00120123012301234".

Originally Posted by tabstop

It's impossible to answer the question "why is the output 0012012012301234", because the output is not "00120123012301234".

Sorry, I meant 001012012301234

Well, what else did you expect? (Trace through the logic: what is printed for b(0), for instance?)