Thread: Syntax for pointing to a array and acessing its elements

These are different:

Code:

int *myArray[10];
int myArray[10];

The first is an array of pointers to integers. The second is an array of integers.

Do you want a pointer to point at an array of integers?
If so you can do like this:

Code:

int main()
{
        int array[3] = {1,2,3};
        int *ptr;

        ptr = array;

        printf("%d\n", *ptr);
        printf("%d\n", *ptr+1);

        //or perhaps better, like this
        printf("%d\n", ptr[0]);
        printf("%d\n", ptr[1]);


        return 0;
}

Originally Posted by papagaio

Ah, thank you! Just to make sure I'm making sense of pointers, would this be correct:

Code:

int *MyArray[10];

for (i = 0; i <= 10; i++)
{
    myArray[0] = (int*)malloc(sizeof(int) );
}

and to access elements:

Code:

 *myArray[0] = 1;
 *myArray[1] = 1;

Close.

Code:

int *MyArray[10];

for (i = 0; i <= 10; i++)
{
    myArray[i] = malloc(sizeof(int) );
}

Close. But still not right.

Code:

int *MyArray[10];

for (i = 0; i <= 9; i++)
{
    myArray[i] = malloc(sizeof(int));
}

or more commonly:

Code:

int *MyArray[10];

for (i = 0; i < 10; i++)
{
    myArray[i] = malloc(sizeof(*myArray[i]));
}

and the 10 may well be replaced by a named constant.