Hey there!
I have an array of strings where I declare all strings like this:
to represent 2 chars in one variable. All tend to be only 2 bytes long.Code:string[2] = "\xFB\x9D";
What would be the safest&easiest way to count the number of strings in this array? Because they are not \0-terminated I can't use strlen().Code:char a[2] = "\xFB\x01"; char b[2] = "\xFF\x01"; char c[2] = "\xD1\xF5"; ... char *pitems[] = {a, c, f, z};
Thanks in advance,
Hawk
If you do not pass the array to a function, but are in the block where it is defined:
If you do pass the array to a function, you're just out of luck.Code:sizeof(pitems)/sizeof(pitems[0])
Well actually thisis declaring an array of char pointers, so you can easily add a NULL pointer at the end and use that to know hoiw many of them there are in any function this is passed to. E.g:Code:char *pitems[] = {a, c, f, z};Code:char *pitems[] = {a, c, f, z, NULL}; foo(pItems); //... void foo(char** pItem) { while (pItem != NULL) { bar(*pItem); } }
Last edited by laserlight; 10-24-2009 at 03:35 AM. Reason: Closed code tag.
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Linus Torvalds: "But it clearly is the only right way. The fact that everybody else does it some other way only means that they are wrong"
Thank you for the input. I (finally) added both methods to my program to find them if I need them in another program also. Yet I don't know why sizeof(pitems)/sizeof(pitems[0]) wouldn't work if I passed the array to another function.
Since arrays sizes degrade to pointers when they're passed to a function, the sizeof(arrayName) becomes just the size of the pointer to that data type (int, char, whatever).
