Thread: How to add hours:minutes:seconds (hh:mm:ss) keeping output values <60

I would use the modulus operator (and the division operator), which does not require using if in any way.

hmm, how exactly? Obviously I want to simply add the seconds (or minutes) if the sum of the 2 input values is less than 60, but how do I account for sums greater than 60 without the if:els statement. Sorry I'm a newb.

I currently have the following variables declared: h1, m1, s1 (for 1st user inputted hours:minutes:seconds) h2, m2, s2 (for second user input) and h3, m3, and s3 for the summed output.

does 59%60 equal 0 or 59?

% gives the remainder (and / gives the quotient). Since you will do the exact same thing whether the sum is smaller than 60 or bigger than 60 (use mod to find the remainder and add the carry to the next "unit"), the use of an if is not needed.

Make sure you don't type any punctuation, like : or similar, since you have told the computer (via the format string %d%d%d) that there isn't any.

ohhhhhh. It's supposed to be written for the entry format
"hh:mm:ss"

so i guess I need to change the format string to "%d:%d:%d", huh?

That would be correct.

ok, so I'm just trying to get this to at least do something that makes sense, so I currently have

Code:

     1  #include<stdio.h>
     2
     3  /*
     4  myname
     5  classsection
     6  10-04-09
     7  pe2.c
     8  */
     9
    10  int main(void)
    11  {
    12  int h1, m1, s1, h2, m2, s2, h3, m3, s3;
    13  printf("TIME1# ");
    14  scanf("%d:%d:%d", &h1, &m1, &s1);
    15  printf("TIME2# ");
    16  scanf("%d:%d:%d", &h2, &m2, &s2);
    17  s3=(s1+s2);
    18  m3=(m1+m2);
    19  h3=(h1+h2);
    20  printf("%d:%d:%d", &h3, &m3, &s3);
    21  printf("PROGRAM ENDS\n");
    22  return 0;
    23  }

I know this won't keep the output minute and second values under 60 & carry the remainders, but again I'm just trying to get it to do something correctly for now.

when I compile I get these warnings

Code:

pe2.c: In function `main':
pe2.c:20: warning: int format, pointer arg (arg 2)
pe2.c:20: warning: int format, pointer arg (arg 3)
pe2.c:20: warning: int format, pointer arg (arg 4)

and now when I run it I at least can input both values now, but this is what I get (when I enter 12:12:34 and 34:12:73 obviously)

Code:

TIME1# 12:12:34
TIME2# 34:12:73
-4195092:-4195096:-4195100PROGRAM ENDS

what am I doing wrong in line 20?

printf and scanf are not the same thing, and do not require the same arguments. As your compiler is telling you, %d is an int format and so an int is expected (not a pointer).

Did you ever bother reading the manual on printf and how to pad with 0s?

ahh right, rtfm

sonofab!tch

Code:

#include<stdio.h>

/*
Kevin Gentsch
CS1250-001
10-04-09
pe2.c
*/

main(void)
{
int h1, m1, s1, h2, m2, s2, h3, m3, s3;
printf("TIME1# ");
scanf("%d:%d:%d", &h1, &m1, &s1);
printf("TIME2# ");
scanf("%d:%d:%d", &h2, &m2, &s2);
s3=(s1+s2)%60;
m3=(m1+m2+((s1+s2)/60))%60;
h3=(h1+h2+((m1+m2)/60));
printf("%2.2d:%2.2d:%2.2d\n", h3, m3, s3);
printf("PROGRAM ENDS\n");
return 0;
}

I've got it working perfectly (or so it seems) but the turnin site still doesn't like it. Guess I'll have to talk to the teacher

thanks tho tabstop, you rock