Thread: Incrementing Twice?

  1. #1
    Registered User
    Join Date
    Sep 2009

    Incrementing Twice?

    Hi! So. I am trying to write a program that counts the number of characters entered into the program from the keyboard until EOF. My teacher is having me use the getchar() function. The problem is my program seems to want to increment the count variable twice every time...
    #include <stdio.h>
    int main( int argc, char *argv[] ) {
      int c;
      int count;
      count = 0;
      while ( ( c = getchar() ) != EOF ){
        count ++;
      printf ("\n%d characters were entered.\n\n", count);
      return 0 ;
    So if I entered 3 4 and 5, it would report 6. Does anyone have any ideas why this is happening? Did I just make a really stupid mistake? Thanks in advance.

  2. #2
    and the Hat of Guessing tabstop's Avatar
    Join Date
    Nov 2007
    Because you entered six characters:

    That's six characters. (Maybe the first two were spaces, but the point still holds.)

  3. #3
    C++ Witch laserlight's Avatar
    Join Date
    Oct 2003
    As in you entered 345, then simulated EOF and it reported 6? If you entered 3, then entered 4, then entered 5, the newline characters due to the enters will be counted.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  4. #4
    Registered User
    Join Date
    Sep 2009
    Ah I see. Thank you.

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