Thread: Reading characters from string/file in blocks of 10

Hi,

Would just like to ask about reading characters from string/file.

Say if I have a sequence of 200 letters, how do I get blocks of 10 letters each with the blocks shifting by one position to the right? Example:

First block of 10 letters would be position 1-10 in the string/file.
Second block of 10 letters would be position 2-11 in the string/file.
Third block of 10 letters would be position 3-12 in the string/file and so on until I reach the last possible block.

And once I get those blocks, how do I arrange them neatly in a column in excel format?

Cheers,
Z070111

Hi,

This is what I have done so far...

Code:

#include <stdio.h>

main ()
{
	FILE *from, *in;
	int i;
	char ch[100];

	if ((from = fopen("output2.txt", "r"))==NULL)
		printf("Error opening output2.txt");
	else
		if((in = fopen("input2.xls", "w")) == NULL)
		printf("Error opening input2.xls");
		else
		{
			for(i = 10; i <= 40; i++)
			{
				while(fgets(ch, sizeof (i), from))
				fputs(ch, in);
			}
		}
		fclose(from);
		fclose(in);
}

I need to create blocks of 10 char to 40 char. But it doesn't seem to do that for me but instead it prints out just the whole long sequence.

Another thing is, I need to put these blocks of char into a column of an excel spreadsheet but I can't find much about editting in excel using C.

Anyone can assist?

Thanks much in advance,
Z070111

Doesn't Excel import comma separated values for it's text input, into columns?

For code, I was thinking of something like this, which shows it on the screen.

Code:

#include <stdio.h>

int main ()  {
  int i, j, done;
  char ch[] =  "abcdefghijklmnopqrstu";

  printf("\n\n\n\n\n\n");
 // Use fgets() and put the whole long string into your 
 //(much larger) char array, then:
  i = done = 0;
  while(!done)  {
    for(j = i; j < i+10; j++) {
      putchar(ch[j]);
      if(!ch[j+1]) {
        done = 1;
        break;
      }
    }
    if(!done)
      printf(", ");
    ++i;
    if(i % 7 == 6)
      printf("\n");
  } 
  printf("\n\n\n\t\t\t     press enter when ready");
  i = getchar();
  return 0;
}

Thanks Adak!!!

Your help is much appreciated. =)

Originally Posted by Z070111

Thanks Adak!!!

Your help is much appreciated. =)

You're welcome. I thought that might brighten your day.