Doubt about max, minimum and average value with if function

[georgio777]

Hi,
I started this semester with C programming and one of the assignments asks to find the max value, minimum value and average of 10 integers with range of 0 and 100.

So here is what I did:

int grad0,grad1,grad2,grad3,grad4,grad5,grad6,grad7,grad8,grad9;

	if (grad0 > grad1 && grad0 > grad2 && grad0 > grad3 && grad0 > grad4 && grad0 > grad5 && grad0 > grad6 && grad0 > grad7 && grad0 > grad8 && grad0 > grad9)
			{
				printf("The max value of your grades is: %d\n", grad0);
			}
		else if (grad1 > grad0 && grad1 > grad2 && grad1 > grad3 && grad1 > grad4 && grad1 > grad5 && grad1 > grad6 && grad1 > grad7 && grad1 > grad8 && grad1 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad1);
		}
		else if (grad2 > grad0 && grad2 > grad1 && grad2 > grad3 && grad2 > grad4 && grad2 > grad5 && grad2 > grad6 && grad2 > grad7 && grad2 > grad8 && grad2 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad2);
		}
		else if (grad3 > grad0 && grad3 > grad1 && grad3 > grad2 && grad3 > grad4 && grad3 > grad5 && grad3 > grad6 && grad3 > grad7 && grad3 > grad8 && grad3 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad3);
		}
		else if (grad4 > grad0 && grad4 > grad1 && grad4 > grad2 && grad4 > grad3 && grad4 > grad5 && grad4 > grad6 && grad4 > grad7 && grad4 > grad8 && grad4 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad4);
		}
		else if (grad5 > grad0 && grad5 > grad1 && grad5 > grad2 && grad5 > grad3 && grad5 > grad4 && grad5 > grad6 && grad5 > grad7 && grad5 > grad8 && grad5 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad5);
		}
		else if (grad6 > grad0 && grad6 > grad1 && grad6 > grad2 && grad6 > grad3 && grad6 > grad4 && grad6 > grad5 && grad6 > grad7 && grad6 > grad8 && grad6 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad6);
		}
		else if (grad7 > grad0 && grad7 > grad1 && grad7 > grad2 && grad7 > grad3 && grad7 > grad4 && grad7 > grad5 && grad7 > grad6 && grad7 > grad8 && grad7 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad7);
		}
		else if (grad8 > grad0 && grad8 > grad1 && grad8 > grad2 && grad8 > grad3 && grad8 > grad4 && grad8 > grad5 && grad8 > grad6 && grad8 > grad7 && grad8 > grad9)
		{
			printf("The max value of your grades is: %d\n", grad8);
		}
		else if (grad9 > grad0 && grad9 > grad1 && grad9 > grad2 && grad9 > grad3 && grad9 > grad4 && grad9 > grad5 && grad9 > grad6 && grad9 > grad7 && grad9 > grad8)
		{
			printf("The max value of your grades is: %d\n", grad9);
		}
	if (grad0 < grad1 && grad0 < grad2 && grad0 < grad3 && grad0 < grad4 && grad0 < grad5 && grad0 < grad6 && grad0 < grad7 && grad0 < grad8 && grad0 < grad9)
			{
				printf("The min value of your grades is: %d\n", grad0);
			}
		else if (grad1 < grad0 && grad1 < grad2 && grad1 < grad3 && grad1 < grad4 && grad1 < grad5 && grad1 < grad6 && grad1 < grad7 && grad1 < grad8 && grad1 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad1);
		}
		else if (grad2 < grad0 && grad2 < grad1 && grad2 < grad3 && grad2 < grad4 && grad2 < grad5 && grad2 < grad6 && grad2 < grad7 && grad2 < grad8 && grad2 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad2);
		}
		else if (grad3 < grad0 && grad3 < grad1 && grad3 < grad2 && grad3 < grad4 && grad3 < grad5 && grad3 < grad6 && grad3 < grad7 && grad3 < grad8 && grad3 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad3);
		}
		else if (grad4 < grad0 && grad4 < grad1 && grad4 < grad2 && grad4 < grad3 && grad4 < grad5 && grad4 < grad6 && grad4 < grad7 && grad4 < grad8 && grad4 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad4);
		}
		else if (grad5 < grad0 && grad5 < grad1 && grad5 < grad2 && grad5 < grad3 && grad5 < grad4 && grad5 < grad6 && grad5 < grad7 && grad5 < grad8 && grad5 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad5);
		}
		else if (grad6 < grad0 && grad6 < grad1 && grad6 < grad2 && grad6 < grad3 && grad6 < grad4 && grad6 < grad5 && grad6 < grad7 && grad6 < grad8 && grad6 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad6);
		}
		else if (grad7 < grad0 && grad7 < grad1 && grad7 < grad2 && grad7 < grad3 && grad7 < grad4 && grad7 < grad5 && grad7 < grad6 && grad7 < grad8 && grad7 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad7);
		}
		else if (grad8 < grad0 && grad8 < grad1 && grad8 < grad2 && grad8 < grad3 && grad8 < grad4 && grad8 < grad5 && grad8 < grad6 && grad8 < grad7 && grad8 < grad9)
		{
			printf("The min value of your grades is: %d\n", grad8);
		}
		else if(grad9 < grad0 && grad9 < grad1 && grad9 < grad2 && grad9 < grad3 && grad9 < grad4 && grad9 < grad5 && grad9 < grad6 && grad9 < grad7 && grad9 < grad8)
		{
			printf("The min value of your grades is: %d\n", grad9);
		}
int aver = (grad0+grad1+grad2+grad3+grad4+grad5+grad6+grad7+grad8+grad9)/10;
	printf("The average of your grades is: %d\n",aver);

Imagine that the integers have already a value by doing a scanf.

My problem starts when two or more integers have the same value, the minimum and/or maximum value will not appear.

How can I solve this problem?

Thanks for your help and happy Programming!

[tabstop]

I would start by solving the problem, as opposed to cutting and pasting the same line of code ten times.

If someone showed you ten numbers, one at a time, and then asked you which is largest, how would you answer the question?

[nadroj]

If someone showed you ten numbers, one at a time, and then asked you which is largest, how would you answer the question?

as tabstop suggests, the real difficulty is coming up with a solution to the problem (i.e. nothing to do with programming!). pretend you are the computer, get a piece of a paper and a pencil (and an eraser!) and try to solve the problem. once you have that, it is quite easy to translate it into code. this is what "programming" really is, and dont get discouraged by learning this new language and its syntax.

what is the largest of the following three numbers: 1, 4, 3? how did you come up with your answer? well you simply went through the list one by one and compared them. lets start with an initial "max" value of whatever the first number is, 1. how do we determine that 1 < 4 and 4 > 3, thus the max is 4?

say your requirement was to find the max number, but instead of a list of 10, the list is now 1000, or simply 50. would you continue using your current design?

[georgio777]

as tabstop suggests, the real difficulty is coming up with a solution to the problem (i.e. nothing to do with programming!). pretend you are the computer, get a piece of a paper and a pencil (and an eraser!) and try to solve the problem. once you have that, it is quite easy to translate it into code. this is what "programming" really is, and dont get discouraged by learning this new language and its syntax.

what is the largest of the following three numbers: 1, 4, 3? how did you come up with your answer? well you simply went through the list one by one and compared them. lets start with an initial "max" value of whatever the first number is, 1. how do we determine that 1 < 4 and 4 > 3, thus the max is 4?

say your requirement was to find the max number, but instead of a list of 10, the list is now 1000, or simply 50. would you continue using your current design?

Well with ten numbers is already very complex, so I would find another design.

[nadroj]

Well with ten numbers is already very complex, so I would find another design.

good answer

[georgio777]

Well I was thinking in nested statements, but in this case I have no idea how to start.

[tabstop]

Nested statements is not thinking about the problem. That's not related to finding the answer, that doesn't help you finding the answer, and if you think about the problem you'll realize that.

[georgio777]

Ok, if someone showed you ten numbers, one at a time, and then asked you which is largest, how would you answer the question?

As common sense I would compare all the numbers and simply tell the one that is the biggest.

Am I right?

[tabstop]

Ok, if someone showed you ten numbers, one at a time, and then asked you which is largest, how would you answer the question?

As common sense I would compare all the numbers and simply tell the one that is the biggest.

Am I right?

And how would you compare all the numbers? You can't see them all at one time....

[georgio777]

And how would you compare all the numbers? You can't see them all at one time....

Well, If I am smart enough I will pay more attention to the biggest number as the person is telling me the numbers.

For example is he starts telling 5, 10, 6, 8, 2; I would care about the second one since is the biggest by that moment, if he continues telling number like 5, 15, 11; I would change from 10 to 15 since is now the biggest.

[nadroj]

Well, If I am smart enough I will pay more attention to the biggest number as the person is telling me the numbers.

For example is he starts telling 5, 10, 6, 8, 2; I would care about the second one since is the biggest by that moment, if he continues telling number like 5, 15, 11; I would change from 10 to 15 since is now the biggest.

exactly. for the problem of finding a max (or min) of an unsorted list, which is what your problem is, there really isnt anything special going on. can you translate what you propose the algorithm is into "pseudocode"? that is, simply english statements which mimic the way an algorithm is written? maybe start with:

- create a list (array) with the following numbers: 5, 10, 6, 8, 2
- declare a variable "max" and assign it the first value in the list
- loop over all remaining numbers in the list:
  - if current number ....
    - (do something?)

hope it helps

[georgio777]

exactly. for the problem of finding a max (or min) of an unsorted list, which is what your problem is, there really isnt anything special going on. can you translate what you propose the algorithm is into "pseudocode"? that is, simply english statements which mimic the way an algorithm is written? maybe start with:

- create a list (array) with the following numbers: 5, 10, 6, 8, 2
- declare a variable "max" and assign it the first value in the list
- loop over all remaining numbers in the list:
  - if current number ....
    - (do something?)

hope it helps

Ok, well here is the problem, we haven't seen arrays nether loops still. That's the reason I am concerned and a little bit confused.

Is there is a way to do it without loops nor arrays?

[laserlight]

Yes, so you have an idea right there: you need to keep track of the currently known largest number.

[georgio777]

After some researching and after looking at a similar program code that I founded here. I finally changed the whole C code into arrays and loops. Making less complex and easy to understand!

Wow I learned a lot about arrays today!

Thanks everyone for your help!

I attached the .c file in case you wanted to see it.

Cheers!