Ok I've already spent hours agonising of why my program didn't work and it turned out Switch should have been switch, but the error message "should have ; before {" was not very helpful.
Anyway now I am stuck again, I've made so many errors on this program that have been obvious, only it took me hours to figure out, but I think if this problem is figured out it hopefully will work.
Error message is:
The error applies to the other math functions to, I had to cut the quote short because it printed the smiley faces and there is a smiley face limit.
My program is not finished yet, but still...
Code:
#include <stdio.h>
#include <stdlib.h>
int qadd(int a, int b);
int qsubtract (int a, int b);
int qmultiply (int a, int b);
int qdivide (int a, int b);
int qcheck (int holdans);
main()
{
int score = 0;
int rs; /* Random math operator */
int ran1; /* Random number 1 */
int ran2; /* Random number 2 */
int holdans; /* Get answer from function and insert in another function to check if user guesses correctly */
int i;
for (i=0; i<=9; ++i) /* Ask 10 questions */
{
rs = rand() % 4 + 1; /* Random math operator (+,-,*, /) */
ran1 = rand() % 10 + 1; /* Random number between 1 and 10 */
ran2 = rand() % 10 + 1;
switch (rs)
{
case 1:
qadd(ran1, ran2);
holdans = qadd(ran1,ran2);
printf("\n \n: %d %c %d %c",ran1,'+',ran2,'=');
qcheck (holdans);
break;
case 2:
qsubtract(ran1, ran2);
holdans = qsubtract(ran1,ran2);
printf("\n \n: %d %c %d %c",ran1,'-',ran2,'=');
qcheck(holdans);
break;
case 3:
qmultiply(ran1, ran2);
holdans = qmultiply(ran1,ran2);
printf("\n \n: %d %c %d %c",ran1,'*',ran2,'=');
qcheck (holdans);
break;
case 4:
qdivide(ran1, ran2);
holdans = qdivide(ran1,ran2);
printf("\n \n: %d %c %d %c",ran1,'+',ran2,'=');
qcheck (holdans);
break;
}
}
int qcheck (holdans)
{
int guess;
scanf(" %d", &guess);
if (guess == holdans)
{
printf("Correct");
}
else
{
printf("Wrong");
}
}
int qadd (ran1, ran2)
{
int ans;
ans = ran1 + ran2;
return ans;
}
int qsubtract (ran1, ran2)
{
int ans;
ans = ran1 - ran2;
return ans;
}
int qmultiply (ran1, ran2)
{
int ans;
ans = ran1 * ran2;
return ans;
}
int qdivide (ran1, ran2)
{
int ans;
ans = ran1 / ran2;
return ans;
}
}
If it is obvious, please give a clue.
.text+0x106): undefined reference to `qadd'
Originally Posted by hellogamesmaste
Quite often finding a mistake is a matter of inferring what the problem may be based on what error has been generated; C compilers AFAIK make at least two different kinds of passes thru the code, the second one (focussed on semantics) using information from the first one (focussed on syntax). They will spot different sorts of errors. This is why in a 100 line program, you will get thrown a syntax error on line 85 and not find out about a semantic error on line 22 until you fix line 85; the first pass fails.