I have an array of pointers to a struct called p.
Some of the pointers are NULL some aren't and have value. I would like to have an array q which has the exact same values as p does, but not in a way that q[i] points to the same memory location as p[i]. I want q[i]->koef and q[i]->exp to have the same value as p[i]->koef and p[i]->exp but not to be in the same memory space.Code:typedef struct node { int exp; float koef; struct node *next; } monomial; monomial *p[5];
I hope you understand me
I suppose you are talking about a deep copy.
So allocate memory to q using malloc, then use assignments in a loop (or memcpy).
q[i] = malloc(...);
memcpy(q, p, size_of_p);
Originally Posted by Adak
Just chuck it all in a loop.
I'd recommend allocating as you go, otherwise you'll have to keep track of where you started from if you want to free the entire array in one go.
thanks. works like a charm. put it in a loop
Code:for (i=0; i<=n; i++) { q[i] = malloc(sizeof(monomial)); q[i] = p[i]; }
This is wrong. Remember that q and p are arrays of pointers. You're just overwriting q's newly acquired memory with the memory address of p.
It should be
*q[i] = *p[i];
(To dereference each pointer in the array and copy its contents.)
> q[i] = p[i];
I wouldn't be doing that. Copy each element manually, plus g[i]->next is the same as p[i]->next (not q[i]->next :-D
oops. thanks.
