Thread: Beginner question about the Return statement

Before I continue on with my lessons in C, I want to make sure I understand the use of the Return statement within my own functions. From what I understand, when the program encounters the Return statement within function it immediatly returns to the function that called it? or does it return to main()? Also from the examples I've seen, something like Return( 1 + 4 ); would return the value "5" to the Function name the Return statement was part of? Therefore, you can use a Function name within a printf statement to display a value? So that means a function can be used to same as any variable I'm assuming?

Is my logic correct on this? And would the program below work (and make sense)?

Code:

#include <stdio.h>

int AddNumbers ( int x, int y );


int main ( ) {

printf( "My returned value is: %d\n", AddNumbers( ) );    // calls the function and a value is returned to it

return 0;
}


int AddNumbers ( int x, int y ) {

x = 1;
y = 4;

return( x + y );
}

Returns to the caller (function which called the function which returns). Everything else is correct.
You can even store the return from a function in a variable.

AddNumbers() takes two parameters. You are attempting to call it without passing any parameters.

thanks everyone! i understand the return statement pretty well now. i even corrected my code so it compiles and runs perfectly fine.

Code:

#include <stdio.h>

int AddNumbers( void );


int main( int argc, const char * argv[] ) {
	
	printf( "My returned value is: %d\n", AddNumbers( ) );    // calls AddNumbers function and a value is returned to it
	
	return 0;
}


int AddNumbers( void ) {

        int x, y;
	
	x = 1;
	y = 4;
	
	return( x + y );
}