Thread: sscanf error

Just trying to see what the sscanf does and got stuck with the following program. Though i can understand the error (trying to write to an address which is random , this is what i think). let me know if i am wrong

[insert]

Code:

#include <stdio.h>
#include <stdlib.h>

int main(void)
{
	char * ints = "20, 40, 60";
	char * floats = "10.5,  12.5";
	char * hexs = "FF, F";

	int i;
	int n;
	float f;
	int h;
	char *s;

	n = sscanf(ints , "%d", &i);
	printf("\n %d", i);
	printf("\n sscanf returns %d\n\n", n);

	n = sscanf(floats , "%f", &f);
	printf("\n %f", f);
	printf("\n sscanf returns %d\n\n", n);

	n = sscanf(hexs , "%x", &h);
	printf("\n %d", h);
	printf("\n sscanf returns %d\n\n", n);

	n = sscanf(ints , "%s", s); // ERROR IS HERE 
	printf("\n %s", s);
	printf("\n sscanf returns %d\n\n", n);

	return 0;
}

But how do i overcome it. When i try to assign some address like

s = floats;

still the error persists. Now s is assigned some valid address and i can copy the string from ints to s. But still its the same problem.

Thanks , Yes it works now using malloc but what is wrong with the assignment

s = floats

If i am not wrong floats is now a string literal and its illegal to modify a string literal in C.

Thanks i get it now!