Thread: find at least 4 errors

I need help to find at least 4 errors in the following program;

Code:

#include <stdio.h>

int main( int argc, int argv[])
{
	int i;
	int a;
	
	for ( i = 0; i<argc, i++ )
		printf( "%x \n", argv[i]);
	scanf("%d", a);
	 
	}

Errors highlighted in red - I have found;

Code:

#include <stdio.h>

int main( int argc, int argv[]){

	int i;
	int a;
	
	for ( i = 0; i<argc; i++ );
		printf( "%x \n", argv[i]);
	scanf("%d", &a);

	return 0;
	 
	}

Can you spot anymore?

output of the program is zero.

Originally Posted by Spidey

For loops dont require a semicolon after them, that was not an error. Its looping through all the command line arguments and printing them out in hex. Which you might want to think about. Also look at your function prototype. Anything look odd ?

I would appreciate it if you would just tell me, whats missing?

Is it the parameter of argv to contain the strings which is [i]?

Code:

#include <stdio.h>

int main( int argc, int argv[ i ]){

	int i;
	int a;
	
	for ( i = 0; i<argc; i++ )
		printf( "%x \n", argv[i]);
	scanf("%d", &a);

	return 0;
	 
	}

is it the void function or #include <unistd.h>?

Originally Posted by Lego_TeCh

is it the void function or #include <unistd.h>?

You don't have a void function. Search the internet for the proper way to declare the main() function in C.

Seems like nobody knows.

Originally Posted by Spidey

Yep, Seems like it.
Maybe you should try doing your homework yourself.

Why the arrogance! eewww

I need help to find at least 4 errors in the following program;

Since the compiler normally tells you where the 4 errors would be I'm assuming this is homework.

Put the code in a compiler and compile it. You will see all the errors you need.

Seems like nobody knows.

What's funny is if you type "main function" into google, and hit "I'm feeling lucky", it will give you the answer. Nobody likes someone who can't think for them self, that's why no one is giving you the answer.

Seems like nobody knows.

More like nobody cares. Do your own work.