Thread: Storing Cstrings in an Array

How would I go about storing ctrings in an array with a structure? Here is how it might look in C++.

Code:

#define RANDOM_NUM		((float)rand()/(RAND_MAX+1))

string	GetRandomBits(int length);

using std::string;

struct name
{
      string str;
}

int main()
{


        name array[20];
for(int i=0; i<20; i++)
{
         array[i].str= GetRandomBits(150);
}
}
string	GetRandomBits(int length)
{
	string bits;

	for (int i=0; i<length; i++)
	{
		if (RANDOM_NUM > 0.5f)

			bits += "1";

		else

			bits += "0";
	}

	return bits;
}

Thanks

If you need full flexibility, then just store a char*. If you don't need, say, the ability to resize the string, then just use a char array.

The thing is that C unlike C++ doesn't provide any operators for processing a string of characters as a unit. What you intend to do can be done by defining the struct to be an array of characters, as in

Code:

typedef struct {char str[100];} name

I was referring more to the actual array assignment. I tried using strcpy() which didn't work. I think malloc() may help but I am not sure.

If you use char* then malloc() is necessary. If you use char arrays then you are required to not use malloc. Either way strcpy does work.