Thread: sum problem

The order you do things in C is important. The value of c is calculated before the input of a and b, so what value do you think c will have?

--
Mats

Originally Posted by sk8harddiefast

Code:

#include <stdio.h>
main()
{
char operator;
int a,b,c;
printf("give the operator:");
scanf("operator");
if (operator='+')
{
     printf("give first number:");
     scanf("%d",&a);
     printf("give second number:");
     scanf("%d",&b);
     c=a+b;
     printf("the result is:");
     printf("%d",c);
     printf("\n");
}
else if (operator='-')
{
     printf("give first number:");
     scanf("%d",&a);
     printf("give second number:");
     scanf("%d",&b);
     c=a-b;
     printf("the result is:");
     printf("%d",c);
     printf("\n");
}
else if (operator='*')
{
     printf("give first number:");
     scanf("%d",&a);
     printf("give second number:");
     scanf("%d",&b);
     c=a*b;
     printf("the result is:");
     printf("%d",c);
     printf("\n");
}
else if (operator='/')
{
     printf("give first number:");
     scanf("%d",&a);
     printf("give second number:");
     scanf("%d",&b);
     c=a/b;
     printf("the result is:");
     printf("%d",c);
     printf("\n");
}
   }

run it and plz tell me what's going wrong because is difficult for me to explain the problem in english.

I would llike to suggest a lot of things in your code:
1. scanf takes the address of the variable and syntax is similar to printf.
2. You are asking the user to input a and b in each case. It would have been better to ask for a and b before asking for the opeartor. This way you would have saved time in typing the code.
3. Instead of if and else if, I would suggest to use switch-case(if you have studied it) here.
4. return int explicitly from main.