oops output plz...
main()
{
int k=35;
printf("\n%d%d%d",k==35,k=50,k>50);
}
output
0500 how is tat?..why cant it be 1500
main()
{
int x=15;
printf("\n%d%d%d",x!=15,x=20,x<30);
}
output 1201
please explain this code and output
for k==35 it is true o/p should be 1
for x!=15 it is wrong it should be 0...how?..plz
>> 0500 how is tat?..why cant it be 1500
The standard doesn't dictate the order that the arguments to a function are evaluated. In your case, the assignment was executed first.
Also, 'main' returns an int, and you need to place you code within code tags and indent it so that it's more readable.
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
hi sir,
I will change my code editing..here k==35 ,it is true but the output is 0..the same in next code
we know x=15,but it is x!=15 then it is false ans should be 0
Post your current code and your current output. Post the well indented code in [code][/code] bbcode tags.
Last edited by laserlight; 07-01-2009 at 06:02 AM.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
>> here k==35 ,it is true but the output is 0
Let me give you an example:
You might expect the output to be:Code:#include <stdlib.h> #include <stdio.h> void foo( int, int, int ) { } int bar( const char* text ) { puts( text ); return 0; } int main( void ) { foo( bar( "one" ), bar( "two" ), bar( "three" ) ); return 0; }
"one"
"two"
"three"
But in fact, the compiler is free to execute the functions in *any order* that it pleases.
Code:#include <cmath> #include <complex> bool euler_flip(bool value) { return std::pow ( std::complex<float>(std::exp(1.0)), std::complex<float>(0, 1) * std::complex<float>(std::atan(1.0) *(1 << (value + 2))) ).real() < 0; }
thnx
yaa nice job ...i understood...
