Thread: Memset

  1. #1
    Registered User
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    Memset

    I understand that memset sets the first num of bytes in memory block pointed to by ptr with value given.

    Code:
    void * memset ( void * ptr, int value, size_t num );
    Lets say I do the following:

    Code:
    char data[12];		                                      
    memset(data, 0x0A, sizeof(data));
    Would data look something like "10101010101\0"?

  2. #2
    Lurking whiteflags's Avatar
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    You mean in binary? No, but that is a correct decimal representation.

    I'm assuming you don't actually want a character string, but there is no terminating zero either.

  3. #3
    Kernel hacker
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    No, the binary value would be 00001010 00001010 <another 9> 00001010. There will not be any terminating zero, as memset is given sizeof(data), it will fill ALL bytes of the array.

    As a string, you could do the same thing as
    Code:
    char data[12] = "\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n\n"
    Again you there is no terminating zero, as there is 12 newlines in the array.

    --
    Mats
    Compilers can produce warnings - make the compiler programmers happy: Use them!
    Please don't PM me for help - and no, I don't do help over instant messengers.

  4. #4
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    Thanks guys.

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