'\0' is an int. Character literals in C are ints.
'\0' is an int. Character literals in C are ints.
Hi, Im experiencing a slight issue, this maybe what you guys were discussing. The loop works nicely except that when two zeros are multiplied the loop breaks. Is "digit != '\0'" not the correct condition for this?
Well, it's the right condition for "stop when the product is 0". As you noticed, that doesn't necessarily mean you're done with the problem. You need to stop when the number you're multiplying by has been reduced to 0.Originally Posted by wankel
that makes a lot of sense, so I changed it from "digit" to "number2", but nothings changed?
example:
101
x101
-----
101
-----
10201
when its supposed to be:
101
x101
------
101
10100
------
10201
edit: nevermind, im so dumb. got it solved.
Last question, im having it display the product only if its not the final answer or a zero, so I have this condition:
if (product != final_product || product != 0)
{
print product
}
however, only the first part of that condition works. zeros are still displayed. Is the formatting wrong? Im not getting any errors when im compiling it
Last edited by wankel; 06-15-2009 at 04:44 PM.
