Thread: noob.please help

Originally Posted by sk8harddiefast

i want to make my first program in C.A program that will calculate two numbers , and show me the result.

this is my code.

Code:

#include <stdio.h>
main()
{
int a,b;
float c;
a=10;
b=3;
c=a+b;
printf ("c=%d");
}

but the result is c=-1079924084

almost correct

your printf statement is wrong.("%f", c);

OK "sk8harddiefast" -- the correct format is %f. Floating point numbers are represented very differently in memory.

i try ("%d", c); but the result was zero and i try ("%f", c); and the result is 13.00000.why with so much zero?

Opps my bad, didn't relieze you used a float for the storing of adding two integers. Cause thats how many 0's are in a floating point number. If you wanted to print just two zeros it would be

Code:

("%.2f", c);

and just change the (2) for how many ever floating points you'd like to have displayed.

That's what a "floating point" number is.

You can control the zero in printf() with:

Code:

printf("%.2f",number);

Now it will look like 13.00

Dang, I should like slow down a bit I suppose. Both my replies on this simple matter was flawed.

Originally Posted by sk8harddiefast

ok.i wrote printf ("%.0f",c); and now i have result 13!!!!thanks

When you are adding two integers the result will always will be an integer, so it is not necessary to declare the result(c) as float. In some machines float may take more bytes than int then also it'll not be a better idea(although it's a small program memory management is not an issue).