Thread: The current exchange rate

hi all


i have an error message in my code ..
the question is :
write a C program that asks for input as US dollars and uses the function to display the output as GBP sterling. The current exchange rate is 1 GBP to 1.5207 USD.

if anyone could help me with it


my code :

Code:

#include <stdio.h>
         
int main(void)
{
 int input = 0;
   do
   {
      printf( "\nPlease enter a dollar amount to exchange to GBP: " );
      scanf( "%d", &input );

      if ( input > 0 )
      
               printf ("Great Britian: = "%f"/ 1.5207\n",GBP);
      
            } while ( input< 20 );
            
         return 0;
}

i asked to do it with this line but i coudn't

Code:

  double gbp_to_usd( double );

thanks

You have to create a function and call it:

Code:

double gbp_to_usd( double in) {
   // Your code here
}

Then you have to call it:

Code:

               printf ("Great Britian: = %f\n",gbp_to_usd(input));

but I think you have something backwards. You are converting from usd to gbp, but the function is called gbp_to_usd?
EDIT: Also check your printf statement. It has closing " when it shouldn't. Do you mean \"

In your post, you try and do it using the line of code: double gbp_to_usd( double );

Have you written that function?

You haven't defined the variable "GBP", from what I can tell, that is meaningless at the moment.

edit: lol. I was too slow :P

well i am trying to do it as u said but still having errors

Originally Posted by Swarvy

In your post, you try and do it using the line of code: double gbp_to_usd( double );

Have you written that function?

You haven't defined the variable "GBP", from what I can tell, that is meaningless at the moment.

edit: lol. I was too slow :P

No i asked to do it with that function ..

Well what have you tried. This isn't a difficult problem. Post what you have tried for converting. We don't do work here for others. We are here to help and give advice.

this is what i have done so far and it works

Code:

 double gbp_to_usd( double );

int main( void )
{
   double usd = 0.0;
   scanf( "%lf", &usd );
   printf( "%.2lf usd is equivalent to %.2lf gbp", usd, gbp_to_usd( usd ) );
}

double gbp_to_usd( double usd )
{
   return ( usd * 1.5207 );
}

thanks

Originally Posted by BB.BB

this is what i have done so far and it works

Code:

 double gbp_to_usd( double );

int main( void )
{
   double usd = 0.0;
   scanf( "%lf", &usd );
   printf( "%.2lf usd is equivalent to %.2lf gbp", usd, gbp_to_usd( usd ) );
}

double gbp_to_usd( double usd )
{
   return ( usd * 1.5207 );
}

thanks

You forgot the part of the code where if %.2lf goes past the hundreth decimal pace it sends the remainder (.00XXXXX) to your personal bank account.

Originally Posted by BB.BB

this is what i have done so far and it works...

I don't think so. Your calculation is still backwards.

1 British Pound Sterling = 1.5207 US Dollar (you said)

To convert US to pound, you'd do US$ / 1.5207.

same solution with functions