Trial and Error

[dboone]

New to C and have been given a small task to complete the question is as follows:

Write a C program that uses an array to store the following values and a loop to display any value which is greater than 50.


insert

#include <stdio.h>
#include <string.h>

int main( void )
{
/* array type is integer */
int value[] = { 20, 40.2, 22, 42.5, 36, 55.78, 39.4, 61, 62, 73.11 };
int counter, total;
for ( counter = 50, total = 50; counter > 50; counter++ )
{
/* counter variable is acting as the array index */
/* add the value of the current array element */
total += value[ counter ];
}
printf( "%d\n", total == counter );
}

This is the soursecode i have managed so far but it only displays an interger of 1,are there any suggestions as to where i may be going wrong? Please help as i am starting to see doubel

[tabstop]

You are printing the value of "total==counter" (which is apparently true, as true will display as 1).

[dboone]

thanks tab does that mean i should declare it greater than total or counter? I have tried either way and still displays as either 0 or 1. Thought i might be going wrong elsewhere

[dboone]

Still not working when compiled,any other suggestions would be great

[tabstop]

If you want to print the value, then print the value itself, not "total==counter" or "total>counter" or whatever.

Also: 1) you probably want to print values of the array, not values of the counter; 2) you need to compare the values in the array to 50, not a total of them; 3) if you need to go through the loop and print, then the print statement needs to occur inside the loop; 4) your for-loop, as it stands now, never happens.

[itCbitC]

Use C's ternary operator "?:" aka conditional expression to print only those values that are > 50.

[linuxdude]

It seems like your question

Write a C program that uses an array to store the following values and a loop to display any value which is greater than 50.

and your code are two different things. Are you trying to just print all values over 50? You don't need a total for that. Your for loop never executes (50 is not > 50). Just go through the array and if array[index] > 50 print else go to next element.

[bvkim]

#include <stdio.h>
#include <string.h>

int main( void )
{
/* array type is integer */
int value[] = { 20, 40.2, 22, 42.5, 36, 55.78, 39.4, 61, 62, 73.11 };
int counter, total;
for ( counter = 50, total = 50; counter > 50; counter++ )
{
/* counter variable is acting as the array index */
/* add the value of the current array element */
total += value[ counter ];
}
printf( "%d\n", total == counter );
}

red: check those value
indigo: un-neccessary part

hope this helps !

[itCbitC]

Still don't get what you're trying to do but there are a few things that jump out.
- the for loop block has no terminal condition ie counter > 50?
- counter >= 50 can't be used as an index for value[] w/o going out-of-bounds.

[Sharke]

Also it looks like value[] should be an array of float or double, not int.

[iMalc]

You actually can't usually write a correct program using trial and error. You have to know what you're doing.
Things to study first:
if-statements
for-loops
printf

Some more stuff not yet mentioned:
A number with a decimal point in it is not an integer. Your array is actually holding this: 20, 40, 22, 42, 36, 55, 39, 61, 62, 73

If you want to know if a value is greater than 50 then you can do this with an if-statement. Do not even consider the ternary operator as itCbitC mentioned.