Looking for a better code

[nhoda911]

OUTPUT display should be:

0 1 2 3
4 5 6
7 8
9

int x=0;

for(x=0;x<=9;x++)
{
  printf("%d",x);
  if(x==3||x==6||x==8)
   {
   printf("\n");
   }
}

is there any way that i can print new line without using the if statement?
or can i have the same output using only loops.. thats my solution with if's i can't get it only with loops.
or maybe im on the right track?

[Snafuist]

is there any way that i can print new line without using the if statement?
or can i have the same output using only loops.. thats my solution with if's i can't get it only with loops.
or maybe im on the right track?

There's a nice solution for arbitrary triangles which only uses two loops. Here's a hint: let the outer loop count from 0 to <length of first row> - 1. The inner loop starts at 0; where does it stop? Use a second variable for storing/incrementing the output value.

Greets,
Philip

[nhoda911]

wew i got it!!! thanks for the tip!
here's my final code:

#include<stdio.h>
#include<conio.h>
int main()
{
clrscr();
int x=4,y=0,z=0;

for(x=4;x>=1;x--)
{
	for(y=1;y<=x;y++)
	{
	printf("%d",z);
	z++;
	}printf("\n");
}

getch();
return 0;
}

is this right? my output is already correct! thanks again.... weew

[Snafuist]

is this right? my output is already correct! thanks again.... weew

That's roughly what I had in mind. Good job :-)

Greets,
Philip

[nhoda911]

thanks again mr. snafuist!!