Thread: is this simple program correct? K&R 1-12

Thanks a lot! What I would like to understand is why if I use the && it doesn't works... shouldn't it be similar to another IF statement?

Originally Posted by matsp

What is not working?

I would expect that you will need a nested if-statement:

Code:

   if (c == ' ' || c == '\t')
   {
     if (pc != c)
       putchar('\n');
   }
   else 
       putchar(c);

This will prevent multiple spaces from giving multiple newlines.

--
Mats

Originally Posted by matsp

Because you do not want the ELSE part to be executed if the second if is false - only if the first if is false.

You could of course add a "if (pc != c)" inside the else-branch instead, but that's less logical.

--
Mats

Mats got exactly what I was looking for, a simple explanation. I'm new to C and all those pointers, includes and so on are totally alien to my current knowledge. But thanks also for the other answerers.