Thread: is this simple program correct? K&R 1-12

Originally Posted by fsx

Code:

	while((c = getchar()) != EOF)
	{
		if((c == ' ') || (c == '\t'))
			putchar('\n');

What you really want is a "nop" (no-op, no operation) and to continue --

Code:

		if((c == ' ') || (c == '\t'))
			continue;

Except you still need a line break! So maybe

Code:

#include <stdio.h>

int main(void)
{
	int c;
	char flag=0;

	while((c = getchar()) != EOF)
	{
		if((c == ' ') || (c == '\t'))
			if (flag) continue;
			else { putchar('\n');
				flag=1; }
		else {	putchar(c);
			flag=0; }
	}
	return 0;
}

If you are just on chapter 1 you may not know about "continue" (it just starts the loop again without doing anything else).

The use of a flag is a very handy, basic, chapter 1 kind of thing, so if you don't understand what that's about, try to, or ask and I'll explain.

Basically now you could type:

Code:

this       is     a   sentance   with  extra      spaces
Output:
this
is
a
sentence
with
extra
spaces