Thread: malloc question..

  1. #1
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    malloc question..

    hat the plus 4 means in the last part
    how it change the number of cells in the "i" row??

    Code:
    int **arr;
    arr=(int**)malloc(... )
    for i=0..
    arr[i]=(int*)malloc(sizeof(int)+4);

  2. #2
    Registered User Maz's Avatar
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    You should *REALLY* learn to read manuals. Why don't you try searching for example for "man malloc" with google?

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    i know that if its *4 then
    4 cells

    what if +4
    ??

  4. #4
    Registered User Maz's Avatar
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    read the documentation of malloc as I said. It tells what the sole argument of malloc means.

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    i know what it means .
    i know that +4 means adding 4 bits

    how it change the number of cells in the "i" row??

  6. #6
    Registered User Maz's Avatar
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    It does not add 4 bits. It adds 4 bytes.

    And you get the answer when you think how many bytes one item in your array needs.

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    integer is 8 bytes
    so it doesnt add any new cells??

  8. #8
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    there's not a fixed size for int. It's usually 4, but can be different in other systems. That's why sizeof() exists, it's a function that returns the size (in bytes) of a data type.

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    integer is 8 bytes
    so it doesnt add any new cells??
    It's 8 bytes on a 64-bit system. It's 4 bytes on a 32 bit system.

    We can't really tell you if it adds new cells. The call just returns a pointer to a certain area in memory equal to the size you specified. It's impossible to tell if that's what you want and what you mean by adding cells - because it depends on how you work with that area of memory.

    You should *REALLY* learn to read manuals.
    Why don't you, by the way? You've been asked this many times, and you seem to make no improvement towards helping yourself.

  10. #10
    Registered User Maz's Avatar
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    Actually, integer is standardized to 4 bytes. But pointer to integer may be 4 or 8 bytes (or something else) depending on the machine's architecture.

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    Quote Originally Posted by Maz View Post
    Actually, integer is standardized to 4 bytes. But pointer to integer may be 4 or 8 bytes (or something else) depending on the machine's architecture.
    No it's not. I've used systems where an integer has been 8 bits, 16 bits, 32 bits, and 64 bits.

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    Officially An Architect brewbuck's Avatar
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    Quote Originally Posted by Maz View Post
    Actually, integer is standardized to 4 bytes. But pointer to integer may be 4 or 8 bytes (or something else) depending on the machine's architecture.
    Not standardized... Just common. Most compilers I've used on x86-64, for instance, default to a 32-bit integer type (you must specify "long long" to get 64 bits) but this is not specified by the standard.

    Other 64-bit architectures I've worked with default to 64-bit integers. Sometimes the compiler lets you select.

    You should not assume anything, especially when somebody can change it via compiler switch.
    Code:
    //try
    //{
    	if (a) do { f( b); } while(1);
    	else   do { f(!b); } while(1);
    //}

  13. #13
    Registered User Maz's Avatar
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    Quote Originally Posted by bithub View Post
    No it's not. I've used systems where an integer has been 8 bits, 16 bits, 32 bits, and 64 bits.
    Youre right. int size is not standardized. Apologies

    I guess I should use uint32_t from now on (as if it was supported by all libraries...)
    Last edited by Maz; 04-15-2009 at 02:26 PM.

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    Doesn't that standard say that int is the natural word size of the processor? In other words, a pointer and an int should always be the same size? And a 64-bit compiler should always make a 64-bit int?

    That's what I understood, but it sounds like I'm mistaken?

  15. #15
    Registered User Maz's Avatar
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    I won't say a word about standard anymore But that really is not the case. I've been doing some hell of a porting work to get pointer arithmetics working after we changed from 32bit arch to 64 bit arch... (there were pointers casted to ints, and then calculated some offsets && casted them back. Also we had some ID numbers for things, and actually those IDs were then used as memory locations... A mess...

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