Thread: Why isn't this an error?

Originally Posted by Cell

Code:

#define MEMBER_SIZE 500

struct table{
   double num;
   struct table *next_table;
}

struct table member_tables[MEMBER_SIZE];

Wouldn't the first struct give an error since it's declaring itself in the middle of it's own declaration?

this is the typical syntax to write a linked list in C. As for whether or not the compiler should complain, all you're really telling the compiler is that you are declaring another variable, in this case a pointer thats gonna hold the addy of a struct table type. so the short answer is no. I'm sure someone more knowledgeble on here could give you the loooonnnnnger answer.

next_table is a pointer to a table, not a table

Actually, the posted code is missing a semicolon.

--
Mats

Originally Posted by Cell

I see what you guys are saying. Because *next_table is creating a pointer of type table, not a new table, it is valid.

caroundw5h, the link you included seems to just be an overview of stdio.h. Do you have a good source regarding linked lists in this manner?

Thanks!

Well there is always google. However this here seems to be a standard reply around here.