Thread: binary to decimal

fflush(stdin) is undefined - see FAQ

bit manipulations better to do using bit-oparations like | ~ & >> <<

show your attempt to convert binary to decimal and we will help to fix errors...

or search form for samples - there are a lot (twice per month at least this question is discussed)

hi, I finished writing the code but it seems I am trying to hard.. I am trying it to make it less complicated but this is what I got so far,

Code:

#include <stdio.h>
#include <stdlib.h>
#include <math.h>

int main()
{
    int n,i,temp1,temp2,temp3,temp4,temp5,remainder,j,k,p,count,count2,a;
    double bits;
	bits = pow(2,n);

	printf("Please enter an integer between 1 and 33:");
	scanf("%d",&n);

    bits = pow(2,n);
 
	printf("\nNumber n of bits in the integers: %d\n",n);
	printf("Number of integers with n=4 bits: %d\n",bits);

	printf("\n\nAll integers with 0 bits equal to 1 listed in ascending order:\n");

	i = 1;	
    temp1 = n;
    temp2 = n;
    
    
     printf("0\t");
    
	while (temp1 != 0)
	{
          printf("0");
		  temp1--;
	}

	printf("\n\n");

	int l;
	
    for(l=1;l<=n;l++)
	{
         printf("All integers with %d bits equal to 1 listed in ascending order:\n",l);
         i=1;
         
         while(i != bits)
         {
                 
                 int temp3 = i;
                 int temp4 = i;
                 int count = 0;
                 
                 while(temp3 != 0)
                 {
                                temp3 = temp3 / 2;
                                count++;
                                
                 }
                 
                 int k = count - 1;
                 
                 int sum = 0;
                 int count3 = 0;
                 
                 while (count != 0)
                 {
                       int power1 = (int) pow(2,k);
                       double power2 = pow(10, k);
                       
                       int a = temp4 / power1;
                       
                       temp4 = temp4 % power1;
                       sum = sum + a * power2;
                       
                       if(a == 1)
                       {
                            count3++;
                       }
                       
                       k--;
                       count --;
                 }     
                       int need1 = sum;
                       
                       
                       if (count3 == l)
                       {
                                  int f;
                                  
                                  printf("%d\t",i);
                                  
                                  count2=0;
                       
                                  while (need1 != 0)
                                  {
                                        need1 = need1 / 10;
                                        count2++;
                                         
                                  }
                                  f = n - count2;
                                  
                                  
                                  while(f != 0)
                                  {
                                          printf("0");
                                          f--;
                                          
                                  }   
                                  printf("%d\n",sum);
                       
                       }
                       
                 
                 i++;
         }
    printf("\n");    
    }
    system("pause");
}

can you help me make this more understandable for other people to understand without having to trace its every move =S