Thread: convert char array to int array

What is the best method to do this? This is my attempt, which failed by the way .

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX 5

int main (int argc, char *argv[])
{
int i;
char core[MAX];
int coreint[MAX];
strcpy (core, argv[1]);

        for(i =0; i < MAX-1; i++)
                coreint[i] = atoi(core[i]);

printf("%d\n", coreint[1] + coreint[2]);
return EXIT_SUCCESS;
}

I'm trying to convert a command argument to a set of integers, eg ./program 417 causes

coreint[0] = 4
coreint[1] = 1
coreint[2] = 7

which are all integers.

Any assistance is appreciated.

Thanks, so would argv[1][i]; turn the string into an integer, I'm not entirely sure what that does. I modified the code:

Code:

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define MAX 5

int main (int argc, char *argv[])
{
int i;
char core[MAX];
int coreint[MAX];
core = argv[1][i];

        for(i =0; i < MAX-1; i++)
                coreint[i]=core[i]-'0';

printf("%d\n", coreint[1] + coreint[2]);
return EXIT_SUCCESS;
}

But the compiler refuses to set core = argv[1][i]; Lastly, what is the -0 for in coreint[i]=core[i]-'0';?

Thanks again!