Thread: Lvalue required

  1. #1
    Registered User
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    Lvalue required

    I'm not sure why I get this error...

    Code:
    typedef struct pcb {
    	char name[11];
    	int  pclass;
    	int  priority;
    } pcb;
    
    int main() {
      pcb *new_pcb = allocate_pcb(); //allocates memory for structure
    
      new_pcb->pclass = 1;
      new_pcb->priority = 2;
      new_pcb->name = "newpcb1";  //error on this line : Lvalue required
    }
    how do I assign the value of name inside the structure?

  2. #2
    C++ Witch laserlight's Avatar
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    You cannot assign to an array, so you should use strcpy() or strncpy().
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
    Look up a C++ Reference and learn How To Ask Questions The Smart Way

  3. #3
    Hurry Slowly vart's Avatar
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    Quote Originally Posted by gmrnetworks View Post
    You can't create structure name s the same as the reference of structure. You have define the other name.
    if you mean that

    Code:
    typedef struct dcb dcb;
    is incorrect - you are wrong;
    you can make a dcb type synonim of the struct dcb type
    All problems in computer science can be solved by another level of indirection,
    except for the problem of too many layers of indirection.
    – David J. Wheeler

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