Thread: How to do the option for Yes and No?

It depends on whether you want to require 'y', 'Y', 'n' and 'N' as valid input. Either way, you would use at least one loop.

use a while loop

Code:

  printf("Would you like to continue (Y/N)?");
  scanf("%c", &ans);

  while (ans == 'y' || ans == 'Y'){
    /*code to be repeted*/
    
    printf("Would you like to continue (Y/N)?");
    scanf("%c", &ans);
  }

edit:

also

Code:

    printf("\\n*         WELCOME TO THE GROCERIES SHOP             *");

will output

Code:

"\n*         WELCOME TO THE GROCERIES SHOP             *"

you have a extra '\'


(from post below mine)

Originally Posted by itCbitC

scanf() requires pointers to the conversion format.

the '&' symbol in front of the variable (you used it inside the if statement but left it out when you asked for ans)

scanf("%c"

will leave \n char in the buffer, which will be read by gets

you need to clear the buffer before reading string - read FAQ how

And while you'll be there - read why you should not use gets

And why you should not use void main

Originally Posted by Vast87

I cannot get gets() to work in while loop, any get arounds?

do not use gets - use fgets

do not mix it with scanf

Code:

#include <stdio.h>

void myflush(void);

int main()
{
	
	int choice;
	char name[30];

	printf("Would you like to continue? Type 0 to stop or 1 to continue: ");
	;

	while(scanf("%d", &choice) == 1 && choice == 1)
	{
		printf("Enter customer name: ");
		scanf(" %29[^\n]",name);	
		printf("Customer Name: <%s>\n", name);
		myflush(); /* if name is longer then buffer - need to get rid of the rest of chars */

		printf("Would you like to continue? Type 0 to stop or 1 to continue: ");
	}

}

void myflush(void)
{
	int c;
	while((c=getchar()) != EOF && c != '\n');
}

fflush for stdin undefined - read FAQ

I would change it to something like this:

Code:

#include<stdio.h>
#include<string.h>


int main()
{
     char customer_name[30], x, y, n, choice;
     float weight, price, payment, total =0;
    
    
     do 
          {
    
          printf("\n********************************");
          printf("\n**  WELCOME TO GROCERIES SHOP   **");
          printf("\n********************************");
    
     
          printf("\nEnter customer name: ");
          scanf(" %s",&customer_name);
             
          printf("\nEnter weight [KG]    :  ");
          scanf(" %f",&weight);
                
        
          printf("\n-------------------------------");
          printf("\n-     BILLING RECEIPT         -");
          printf("\n-------------------------------");
                
          printf("\nCustomer name     :%s", customer_name);
          printf("\nLaundy weight [KG]:%.2f",weight);
                 
          //nested if
                  
          if (weight<=3.0)
             {
             printf("\nPrice equals to :$ 1.20");
             price==1.20;
             }
               
          else if (weight>3.0 && weight<6.0)
             {
             printf("\nPrice equals to :$ 1.00");
             price==1.00;
             }
                    
          else 
             {
             printf("\nPrice equals to  :$ 0.80");
             price==0.80;
             }
                   
          payment = price * weight;
          total += payment;
          payment = 0;
                   
            
          printf("\nWould you like to continue [Y/N] : ");
          scanf(" %c",&choice);
     }while(choice=='y' || choice=='Y')
 
     printf("\n-------------------------------");
     printf("\n-    TODAY'S SUMMARY          -");
     printf("\n-------------------------------");
     printf("\nTotal:%.2f" total); 
                
     printf("\n----------------------------");
     printf("\n-       Thank you          -");
     printf("\n----------------------------");
                   
               
     getch();
     return 0;
}

What would no mean, to a customer? Early exit before going through the do loop?

My "Thank You" is outside the do while loop. You will only see it once.

Oh yeah. No fflush is needed in this version.

Adak - The Yes No at the start is to ask and check whether there is any customer at that time. Thank you Adak for helping me out!

This is the latest code i've been working on. Everything looks ok, but if the user enter name that have 2 or more such as - Jackie Chan or Edward Scissor Hands , the Weight per [KG] will be skip.

No problem for single name such as Jack, Donald, Fatimah.

How can i fix this?

thank you

Code:

#include<stdio.h>
#include<string.h>


void main()
{
     char customer_name[30], y, n, choice;
     float weight, price, payment, total=0;
     int customer=0;
    
         printf("\n******************************************");
         printf("\n**        WELCOME TO GROCERIES SHOP      **");
         printf("\n******************************************");
         
        
         printf("\nWould you like to continue? [Y/N]:  ");
         scanf("%c",&choice);   
         
         while(choice=='y' || choice=='Y')
         
          {
              
         printf("\nEnter customer name              :  ");
         scanf("%s",&customer_name);
         printf("\nEnter weight [KG]                :  ");
         scanf("%f",&weight); 
                
        
         printf("\n------------------------------------------");
         printf("\n-            BILLING RECEIPT             -");
         printf("\n------------------------------------------");
                
         printf("\nCustomer name                    : %s  ",&customer_name);
         printf("\nLaundy weight [KG]               : %.2f",weight);
                
                               
         //nested if
                  
         if (weight<=3.0)
         {
         printf("\nPrice per [KG]                   :$ 1.20");
         price=1.20;
         }
               
         else if (weight>3.0 && weight<6.0)
         {
         printf("\nPrice per [KG]                   :$ 1.00");
         price=1.00;
         }
                    
         else 
         {
         printf("\nPrice per [KG]                   :$ 0.80");
         price=0.80;
         }
                   
         payment = price*weight;
         total = total + payment;
         
         printf("\nPayment                          :$ %.2f ",total);
                       
        
        
         fflush(stdin);
         printf("\nWould you like to continue [Y/N] : ");
         scanf("%c",&choice);
         
         customer++;
         
                 
         
      }
         printf("\n------------------------------------------");
         printf("\n-            TODAY'S SUMMARY             -");
         printf("\n------------------------------------------");
         printf("\nTotal Payment  :$ %.2f " ,total); 
         printf("\nTotal Customer : %d  " ,customer); 
                
         printf("\n------------------------------------------");
         printf("\n-               THANK YOU                -");
         printf("\n------------------------------------------");
                   
               
      getch();
     
}