Hello,
I' trying to convert hexadecimal to binary, I'm using itoa and it seems to be working right, the problem is that it skip every zero at the left of the first one. Is there any way to force it to write this zeros?
if str2="f" everything is Ok, it prints 1111Code:printf("%s ", itoa(str2 , str, 2) );
if str2="2" it prints only 10, I would like to print 0010
Thanks in advance
check the strlen() of received string and do the loop:
for (i = 1; i <= 4 - strlen(itoa(...))); i++)
printf("0");
I think that the most efficient option in this case would be to not use itoa. It's not designed for what you want. Just declare a mask variable, make a loop that loops until the mask is zero, shifting it right each time, then test each bit of the input by anding it with the mask.Code:char buffer[16], len= 0; for (int mask = 0x8; mask > 0; mask >>= 1) { buffer[len++] = (input & mask) ? '1' : '0'; } buffer[len++] = '\0';
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better to make mask unsigned int
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sorry to both you, but i just joined the fourm and i am wondering how do i start a new post because i have a question with my code? thanks
Press new thread where the rest questions are. Search and you will see it
