Evaulating a char string?

[motionman95]

Is is done like this? I can't get it to work.

if(char[] == "I love cheese."){
}

[Adak]

Is is done like this? I can't get it to work.

if(char[] == "I love cheese."){
}

Don't we wish!

A char is a single letter or digit, so no go. Strings in C *must* be elevated to string status by the use of the end of string marker: '\0'.

This:
char *string = {"I love cheese"};

has the end of string marker automatically applied to it. Certain string functions will do this, as well. scanf() and fscanf() are two that come first to mind. fgets() will, if there is room for it.

Anyway, to compare strings in C:

if(strcmp(string1, string2) == 0)  //strings match
if(strcmp(string1, string2)  > 0)  //string1 is greater
if(strcmp(string1, string2)  < 0) //string2 is greater

result = strcmp(string1, string2);  //can be used this way, as well
if(result == 0)
   //strings are a match
else if(result > 0)   //string1 is greater
else
   //string2 is greater

You'll need to include the header file <string.h>, (usually, compiler's vary) to use strcmp().

If you only need to /want to compare the first N char's of each string, then you can use the "sister" function strncmp().

Pretty spiffy, eh?

[motionman95]

This is da best C forum EVA!!!! Thanks man!

[Elysia]

Adak, why do you keep showing off string literals as non-const? Clearly, this is bad practice to teach newbies.