In below code, I am getting following error.. why it happens? .. i
How to assign it to pointer str? [ without changing a[5][10] to other notation]
cannot convert `char (*)[10]' to `char**' in initialization
Code:
int main()
{
char a[5][10]={"One", "Two", "Three", "Four", "Five" };
char **str=a; // This is not Ok ???
char *b[5]={"One", "Two", "Three", "Four", "Five" };
char **str1 = b; // this is Ok
printf("%d %d %d %d\n", sizeof(a), sizeof(str), sizeof(b), sizeof(str1));
printf("%p %p %p %p %p %p\n", a, str, &a[1], &str[1], &a[1][1], &str[1][1]);
printf("%p %p %p %p %p %p\n", b, str1, &b[1], &str1[1],
&b[1][1], &str1[1][1]);
getchar();
return 0;
}