Thread: doubt in printf ??

  1. #1
    C is Sea. I know a drop! ganesh bala's Avatar
    Join Date
    Jan 2009

    doubt in printf ??

    I m getting only "This is". as output.

    How ????
    printf("This is \x0x65 C \x0x66");

  2. #2
    C++ Witch laserlight's Avatar
    Join Date
    Oct 2003
    What did you expect to get? Note that '\x0' is 0, so you are effectively terminating the string at that point.
    Quote Originally Posted by Bjarne Stroustrup (2000-10-14)
    I get maybe two dozen requests for help with some sort of programming or design problem every day. Most have more sense than to send me hundreds of lines of code. If they do, I ask them to find the smallest example that exhibits the problem and send me that. Mostly, they then find the error themselves. "Finding the smallest program that demonstrates the error" is a powerful debugging tool.
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  3. #3
    Registered User
    Join Date
    Oct 2008
    Quote Originally Posted by ganesh bala View Post
    I m getting only "This is". as output.

    How ????
    printf("This is \x0x65 C \x0x66");
    is this what you want to see? if not.. tell us

    printf("This is %c %c %c", '\x0x65', 'C', '\x0x66' );

  4. #4
    Kernel hacker
    Join Date
    Jul 2007
    Farncombe, Surrey, England
    If you want to show hex character 0x65, then you should use \x065. As it stands, character constants are malformed. The compiler doesn't detect it, as it is technically a valid string. In $l4xklynx post, it turns to a multi-character constant, and it is probably undefined behaviour exactly what it prints in this case.

    Compilers can produce warnings - make the compiler programmers happy: Use them!
    Please don't PM me for help - and no, I don't do help over instant messengers.

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