Thread: Quick Question: 2D Array with char **

Quick Question
I have some functions who take as parameters an int and and a char **. Basically the work in the same line of thought as main in c. I pass the number of arguments and the arguments themselves as strings.

So in my main program I had declared a char ** arguments and I allocated space with malloc and stored the arguments input from the user in there but then I tried to declare it as a char[8][16] because malloc seemed unneeded and I was told that it was probably unneeded to alloacate space in the stack but I get an error now while compiling that the argument passed in the functions is incompatible type. How do I pass a 2d array as a pointer to a function?
Also I tried to change the parameter to a char[][] but I think that you need the size of the second []
like so char[][16] right.
But the think is I dont want to pass a copy of an array of strings or am I being unreasonbale. I know that nowadays an array of string isn't much of space but I think it would be preferable to pass pointers and the thing is that I store the arguments in another function so if I pass a copy I wont succed anything

the function are like this

Code:

int function (int c, char **v)

and the local variable which I pass is

Code:

char arguments[8][16];

A two-dimensional array is not a pointer to pointer - you need a pointer for each of the second dimension elements for a pointer to pointer to act as a two-dimensional array. See my other post in your "Want comments thread" for a suggestion to your SPECIFIC problem.

--
Mats

Code:

int function (int c, char v[][16]);