I get the above warning with the following code. I have used this same process in the past without any warning. I have not been able to eliminate the warning.
Code://FUNCTION int FUPW_f(int *index, int i) //Pulse Width Function { int j; int FPW; if (i > 3) j = 1; else j = 0; FPW = *(index + j); return FPW; } //main int FULPW[8]; int FUPW_REG[2]; int PWOFF; for (i = 0; i < 8; i++) { FULPW[i] = (FUPW_f(*FUPW_REG, i) + PWOFF); } }
FUPW_REG is an array of integers hence *FUPW_REG is the first integer in the array. FUPW_f's first parameter is a pointer to an integer, so what you should probably do is pass FUPW_REG instead of *FUPW_REG since the array would be converted to a pointer to its first element.
By the way, a common convention is to reserve fully capitalised names for macro names.
Look up a C++ Reference and learn How To Ask Questions The Smart WayOriginally Posted by Bjarne Stroustrup (2000-10-14)
laserlight,
When I do that, I get:
warning: passing argument 1 of 'FUPW_f' discards qualifiers from pointer target type
Perhaps you're passing a const pointer to a function that expects a non-const pointer?
dwk
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OK, that's it. I was passing a volatile integer to a non-volatile pointer. It's working now. Thanks.
