Thread: translate int_32 to 8-bit

hello,
So, if I converting ip address from 8-bit to int_32 type.
address = (((((ip[0]<<8)+ip[1])<<8)+ip[2])<<8)+ip[3];
But, which's way reverse that?
I tried this way

Code:

for (;i<4; ++i) id[i] = (address >> (i*8)) & 0xFF;
printf("%u\n", id[i]);

However. I've got a value prefix where has been that ip-address.
How to do converting value from int_32 to 8-bit?

It seems you are doing it correct.
Lets say this ip is stored like this: 0x01020304

Code:

ip >> 0 = 0x04
ip >> 8 = 0x03
ip >> 16 = 0x02
ip >> 32 = 0x01

So you could do something along the lines of this:

Code:

char temp;

    for (i = 0; i < 4; i++)
        temp = (ip >> (8 * i)) & 0xFF;

Could you post the code of how you populate the variable that holds the ip. Also, post what the 32bit ip is, untouched.

Originally Posted by vart

you ar printing id[4] - which is out of bounds access
as well as your i is never reset to 0 on the next iteration of the outher loop

ops, I gaming with it and forgot change it before posted.

Could you post the code of how you populate the variable that holds the ip. Also, post what the 32bit ip is, untouched.

sure

Code:

sscanf(argv[1], "%d.%d.%d.%d/%d", &ip[0], &ip[1], &ip[2], &ip[3], &mask);
degree = 32 - mask;
hosts=1 << degree;

Could you help me?

Are you resetting i in the second for loop, now?

Have you updated the code after incorporating suggestions made by the other posters?