hi,
I just started working with C.
How do we write a C function that matches two strings like ...
$string1 = NY PROD Box;
string2 = NJ PROD Box;
I would like a function that basically will check like perl.
Thank you,Code:if ($string1 =~ "[A-Z]+ PROD Box"){ code }
One way to do it in C would be to have a char array with the string you want to check, and another one have the string you want it to be checked against it. Then use the strcmp() function. If it returns zero, the strings are the same.
You need to include <string.h> and then
where string1 and string2 are pointers to the char arrays base address (name of the array can also be used for this).Code:if((strcmp(string1, string2)) == 0) //it's a matching string
hi
The problem is that the string1 and string2 are not exact match.
Only the last of part ie the "PROD Box " part of the string matches.
so I am not sure if the strcmp works here.
Any other suggestions?
Code:size_t len = strlen(string1); size_t len2 = strlen("PROD Box"); if(len < len2) return 0; if(strcmp(string1+len-len2, "PROD Box") == 0) return 1; return 0;
All problems in computer science can be solved by another level of indirection,
except for the problem of too many layers of indirection.
– David J. Wheeler
The obvious answer.... use regular expressions in C.
Mainframe assembler programmer by trade. C coder when I can.
I think there will be a little problem with the above logic.
What if string1 = "NY TEST Box"
Then the above login will return true even for the NY TEST Box
(Correct me if I am wrong)
Just check if the last 8 chars of the string are "PROD Box". If the string is less than 8 chars it's false by default. Regular expressions are overkill if you just want to match the suffix of two strings.
You're wrong. The last eight characters must match "PROD Box".Originally Posted by vinuk23
