Thread: help me solve/understand this conflicting types error

When I try to compile this:

Code:

/* Exercise 1.15. Rewrite the temperature conversion program of Section 1.2 to use a function for conversion. */

/* C = (5 / 9)(F - 32) */

#include <stdio.h>

main()
{
 int fahr;

 printf("\n\nfahrenheit\tcelsius\n");
 for(fahr = 0; fahr <= 300; fahr = fahr + 20)
	printf("%3d\t\t%3.0f\n",fahr,fahr_cel(fahr));
 printf("\n\n");

 return 0;
}


float fahr_cel(int fahr)
{
 float cels;

 cels = (5.0 / 9.0) * (fahr - 32.0);

 return cels;
}

I get this from the compiler:

Code:

exercise 1-15.c: In function ‘main’:
exercise 1-15.c:13: warning: format ‘%3.0f’ expects type ‘double’, but argument 3 has type ‘int’
exercise 1-15.c: At top level:
exercise 1-15.c:20: error: conflicting types for ‘fahr_cel’
exercise 1-15.c:13: error: previous implicit declaration of ‘fahr_cel’ was here

But I can't find what's wrong with the code. Why does the argument 3 has type int instead of float??

You can't call a function without a prototype. (Well, you can try, but you get what you got.) So put a function prototype at the top of your file.

thanks! (so dumb)

just put main() below...
so you don't have to put prototype...