Yes, that is true.Originally Posted by tabstop
However, this is still not true. It is an array, not a pointer of any sort. Granted, the difference only shows up in the use of sizeof, but there is a semantic difference nonetheless.
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No, it's an array, and not a pointer, therefore you cannot assign an address to it.
If you pass an array to a function, a pointer to its first element is passed instead.
wow... I started an arguement lol, I have looked-up memcpy(), but only found syntax and not examples of how it should be used. However it is late now and I shall post back in the morning. And yes by the way 'same-age' is an array.
I am worried that you believe there is a difference.
a difference to what exactly?
Very well, I shall make an example for you.
You've looked up memcpy, so you know that it will copy n bytes from the source pointed to by the second argument to the destination pointed to from the first argument. Simply calculate your bytes.
Like that. But a loop would work just as well. memcpy is essentially that in a function.Code:#include <string.h> int main() { int age[4] = {59, 89, 23, 20}; int sameAge[4]; memcpy(sameAge, age, sizeof age[0] * 4); return 0; }
A difference between the syntax and how it should be used.
thank you very much for your useful post, the information that memcpy(), is essentially a functions explains fully. And also answers the question to my previous post to 'tabstop'
Incidentally, in this case you could just write:
but the multiplication would be more like what you would do if this were in another function.Code:memcpy(sameAge, age, sizeof sameAge);
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thanks for the help, i have done it this way:
Code:#include <string.h> #include <stdio.h> int main() { int age[4] = {169, 8, 17, 20}; int sameAge[4]; int i; memcpy(sameAge, age, sizeof age); for( i=0; i<4; i++) { printf("%d\n", sameAge[i]); } return 0; }
Last edited by cus; 01-03-2009 at 08:01 AM.
Consequently, it can also be written as:
Which is my preferred method. It also saves you headaches since sizeof something does not work for everything, but sizeof(something) always works.Code:memcpy( sameAge, age, sizeof(age) );
yes thanks, i think i just read that on wikipedia, due to the type name always need to be enclosed in parenthesis i.e.
printf("%u,%u", (unsigned) sizeof c, (unsigned) sizeof(int) );
