printing number from array question..

Then you broke laserlight's code. If you run it, exactly as written, you will actually get 1000.

Quote:

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Originally Posted by transgalactic2

i get 000000000000000000000000000000000000....00001000
when i run your code
i need only 1000
??

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I get 1000 when I run the program whose source code I showed. If you get the leading zeroes, it implies that you are not running my most recent example.

More importantly, you need to understand what the code commented by "Find the first non-zero." and "Print the significant digits." does.

i fixed it

why when i put

Code:

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int digits[50]={9, 1, 100};
it gives me
10019
??

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i changed your code to

Code:

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/* Find the first non-zero. */
    for (i = NUM_DIGITS - 1; i > 0 && digits[i] == 0; --i);
 temp4=i;
    /* Print the significant digits. */
    for (i=49; i >= 0; --i)
    {
                if (temp4>=i){
        printf("%d", digits[i]);
                }
    }
    putchar('\n');

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Quote:

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Originally Posted by transgalactic2

why when i put

Code:

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int digits[50]={9, 1, 100};
it gives me
10019
??

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What output did you expect?

Quote:

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Originally Posted by transgalactic2

i changed your code to

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What do you hope to achieve by making such a change?

i expect
900 +10 +100
1010

??

Since the first 9 means 9 and not 900 that seems like a rather silly expectation.

Quote:

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Originally Posted by transgalactic2

i expect
900 +10 +100
1010

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This is frustrating. It looks like you cannot decide how you really want to interpret the array.

At this point I would like to ask what exactly are you trying to do. What is the point of this whole exercise?

10^2 10^1 10^0 etc..

Quote:

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Originally Posted by transgalactic2

10^2 10^1 10^0 etc..

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That is too vague.

Quote:

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Originally Posted by transgalactic2

10^2 10^1 10^0 etc..

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Yes. And since you start at the right......................