Why does this throw an exception?
It works fine if I use a temporary variable to store pArg, but it seems that I can't do any operations on consts.Code:int isOdd_8(const unsigned int * pArg) { return *pArg & 1; }
Is a temporary variable the way to go?
I can't find any definitive answers on Google.
What do you mean by "throw an exception"? If I copy that code, it compiles and runs perfectly well on my system.
I'm getting "Access violation reading location 0x000000aa" when I give it a value of AA.
Actually, that looks like I've just messed up the pointer, but when I change it to this:
it won't compile, giving me this error:Code:return pArg & 1;
error C2296: '&' : illegal, left operand has type 'const unsigned int *'
I think the error is on the other side -- are you sure you're passing a pointer, and not just an unsigned int? (That is to say, you need to call this as isOdd_8(&intvar).)
Oh, awesome. That one slipped by me, that was it.
Thanks.
I'm amazed that you managed to call isOdd_8( 0xAA ); without getting any warnings either.
If you dance barefoot on the broken glass of undefined behaviour, you've got to expect the occasional cut.
If at first you don't succeed, try writing your phone number on the exam paper.
