Thread: Storing an array of structures?

Originally Posted by itCbitC

Just like you would declare an array of ints for ex. except that each element is of the type struct instead of an int.

Ok say I have this struct..

Code:

typedef struct Operator
{
	char symbol;
	int operands;
	union
	{
		void *f;
		double (*f0)(void);
		double (*f1) (double x);
		double (*f2) (double x, double y);
	}
}Operator;

Operator mult={'*',2,multiply1};
Operator add={'+',2,add1};
Operator neg={'-',1,neg1};
Operator divide={'/',2,divide1};
Operator square={'sq',1,square1};
Operator sqrt={'sqrt',1,squareRoot1};
Operator min={'m',2,min1};
Operator max={'M',2,max1};
Operator expo={'^',2,expo1};
Operator pi={'pi',0,pi};
Operator loga={'log',1,L};
Operator expon={'e^',1,E};

So would it be like this?:

Code:

double main (void)
{
	Operator op[12]={mult, add, neg};
}

etc... ?