help in fixing this code..

I tried to trace it.
and it works on the first loop run.
then on the second loop it give a number which its not supposed.

http://img372.imageshack.us/img372/8783/96751135or0.gif

Code:

---

#include <stdio.h>



int main(){
int count=0;
        int num;  //a number
        int temp;
        int f_num = 0;  //flipped number
        scanf("&#37;d",&num);

do{
if ((num!=f_num)&&(count>0)){
 num=num+f_num;
 temp=num;
 printf("num=%d f_num=%d temp=%d count=%d\n",num,f_num,temp,count);
}
temp=num;
  while(num)
  {
      f_num = 10 *f_num + num % 10;
      num /= 10;
  }
  count++;
  printf("num=%d f_num=%d temp=%d count=%d\n",num,f_num,temp,count);
  num=temp;
  printf("num=%d f_num=%d temp=%d count=%d\n",num,f_num,temp,count);
}while (num!=f_num);
printf("%d",f_num);
return 0;
}

---

I don't even know where to start to try and help you with your code. Try this:

Code:

---

#include <stdio.h>

int flip (int num);

int main (void) {
  int i, j, c = 0;

  fprintf(stdout, "\nEnter the number to flip: ");
  fscanf(stdin, "%d", &i);

  while (i != flip(i)) {
    j = flip(i);
    fprintf(stdout, "%d + %d = %d\n", i, j, i+j);
    c++;
    i += j;
  }

  fprintf(stdout, "Completed in %d steps.\n", c);
  return 0;
}

int flip (int num) {
  int digit, result = 0;

  while (num != 0) {
    digit = num % 10;
    result = result * 10 + digit;
    num /= 10;
  }

  return result;
}

---

Using the original posted code as the template:

Code:

---

/*flip (reverse) the number entered and add it to the last tally. Count the
steps needed (and numbers), until you reach a sum that is the reverse
of itself:

eg: 125 entered: 125+521=646,
646 == it's reverse, so only 1 step was needed.

679 + 976 = 1655
1655 + 5561 = 7216
7216 + 6127 = 13343
13343 + 34331 = 47674
4 steps
*/

#include <stdio.h>

int a[10] = { 0 };

int main()  {
  int count=0, i, j, bad;
  unsigned long int temp, sum;
  unsigned long int num ;     
  unsigned long int f_num = 0;  //flipped number
  printf("\n\n\n Enter a Number: ");
  scanf("&#37;U",&num);
 
  do{
      num=num+f_num;
      f_num = 0;
      temp=num;
      while(temp)  {                   
        f_num = 10 *f_num + temp % 10;
        temp /= 10;
      }
      count++;
      printf("\n num=%lu f_num=%lu count=%d",num,f_num,count);

      //flip the sum into array a[]
      sum = num + f_num;
      temp = sum;
      for(i = 0; i < 10; i++)
        a[i] = 0;
      i = 0;
      while(temp)  {
        a[i] = 10 * a[i] + temp % 10;
        i++;
        temp /= 10;
      }
      i -= 1;
      for(j = 0, bad = 0;j < i; j++, i--)  {
        if(a[j] != a[i]) {
            bad = 1;
            break;
        }
      }
  } while (bad);

  printf("  sum: %lu", sum);

  getch();
  return 0;
}

---

i cant use a function call
so i need to this all in the main function

i tried to change it
but its not working

Code:

---

#include <stdio.h>



int main (void) {
  int i, j, c = 0;
int digit, result = 0;
  printf(  "\nEnter the number to flip: ");
  scanf( "&#37;d", &i);

  while (i != result) {





  while (i != 0) {
    digit = i % 10;
    result = result * 10 + digit;
    i /= 10;
  }

    j=result;
    printf("%d + %d = %d\n", i, j, i+j);
    c++;
    i += j;
  }

  printf( "Completed in %d steps.\n", c);
  return 0;
}

---

Quote:

---

Originally Posted by Adak

Using the original posted code as the template:

Code:

---

/*flip (reverse) the number entered and add it to the last tally. Count the
steps needed (and numbers), until you reach a sum that is the reverse
of itself:

eg: 125 entered: 125+521=646,
646 == it's reverse, so only 1 step was needed.

679 + 976 = 1655
1655 + 5561 = 7216
7216 + 6127 = 13343
13343 + 34331 = 47674
4 steps
*/

#include <stdio.h>

int a[10] = { 0 };

int main()  {
  int count=0, i, j, bad;
  unsigned long int temp, sum;
  unsigned long int num ;     
  unsigned long int f_num = 0;  //flipped number
  printf("\n\n\n Enter a Number: ");
  scanf("%U",&num);
 
  do{
      num=num+f_num;
      f_num = 0;
      temp=num;
      while(temp)  {                   
        f_num = 10 *f_num + temp % 10;
        temp /= 10;
      }
      count++;
      printf("\n num=%lu f_num=%lu count=%d",num,f_num,count);

      //flip the sum into array a[]
      sum = num + f_num;
      temp = sum;
      for(i = 0; i < 10; i++)
        a[i] = 0;
      i = 0;
      while(temp)  {
        a[i] = 10 * a[i] + temp % 10;
        i++;
        temp /= 10;
      }
      i -= 1;
      for(j = 0, bad = 0;j < i; j++, i--)  {
        if(a[j] != a[i]) {
            bad = 1;
            break;
        }
      }
  } while (bad);

  printf("  sum: %lu", sum);

  getch();
  return 0;
}

---

---

i cant use array
and getch()

this is the working code but i need to replace the function calls

Code:

---

#include <stdio.h>



int main (void) {
  int i, j, c = 0;
int digit, result = 0;
  printf(  "\nEnter the number to flip: ");
  scanf( "&#37;d", &i);

  while (i != result) {





  while (i != 0) {
    digit = i % 10;
    result = result * 10 + digit;
    i /= 10;
  }

    j=result;
    printf("%d + %d = %d\n", i, j, i+j);
    c++;
    i += j;
  }

  printf( "Completed in %d steps.\n", c);
  return 0;
}

---

Code:

---

#include <stdio.h>

int flip (int num);

int main (void) {
  int i, j, c,num = 0;
int digit, result = 0;

  printf(  "\nEnter the number to flip: ");
  scanf( "%d", &num);

  while (num != 0) {
    digit = num % 10;
    result = result * 10 + digit;
    num /= 10;
  }


  while (i != result) {

        while (num != 0) {
    digit = num % 10;
    result = result * 10 + digit;
    num /= 10;
  }

    j = result;

    printf("%d + %d = %d\n", i, j, i+j);
    c++;
    i += j;
  }

  printf( "Completed in %d steps.\n", c);
  return 0;
}

---