Thread: Question on passing array arguments to function, and not printing

Originally Posted by tabstop

What do you want this line

Code:

t->fname[90]=*array;

to do? I would think that it would set the ninetieth character of fname to whatever the value of the char pointer passed in was, cast to a character. If you want to copy a string, you should use strcpy.

Yea thanks Tabstop, case closed, i overlooked that assignment, wasnt thinking there, Matt solved the prob! Yea and u are right too, strcpy to copy too, that ota work too

Cheers thanks!