kinda stuck.. help please?

Quote:

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Originally Posted by Salem

Now are you using | because you're too lazy to write ||, or is something else going on here?

| and || are very different animals in C, and casual use of them will just lead you astray.

if ( a || b ) c = 1;
Strange, this is where you started.


> however this latches variable3 to true even when I return variable1 and variable2 to False
This however is wrong. Something else is going on in your program, which has nothing to do with the if statement.
If both a and b are FALSE, nothing happens to c

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sorry, I mean ||, i missed the key.

this is the problem i'm running into. I want

a b c
1 1 1
1 0 1
0 1 1
0 0 0


but, when a and b are 0, c must be able to be 0 or 1 on it's own, independant of a and b.

The story goes:

i turn on either button A or button B and it turn on C. When i turn off button A or B then button C turns off. Now, if I ONLY turn on button C it stays on and I can turn button C off as well.

I think you need a fourth variable.

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Mats

how would i do that?

d = ( !c && ( a || b ) ) || c;

If c is off, you get a or b
If c is on, then a and b don't matter.

what is the 4th variable?

cause i've got button A, B, and C...

Quote:

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Originally Posted by w0nger

what is the 4th variable?

cause i've got button A, B, and C...

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d is the "output" of button C - either C itself is set, or A or B is set, so D represents the output stage of C.

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Mats

the output of D is the button C.

can I just define D as the button C ?

Quote:

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Originally Posted by w0nger

the output of D is the button C.

can I just define D as the button C ?

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Well, I presume you need to know the ACTUAL state of button C as well, right? In which case you need C (the state of the actual button) as well as D (the end result of A, B and C combined).

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Mats

they would be the same.

When D is ON then C is ON
when D is OFF then C is OFF

Quote:

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Originally Posted by w0nger

they would be the same.

When D is ON then C is ON
when D is OFF then C is OFF

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Yes, but D is ON when A or B is ON too, regardless of C.

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Mats

Quote:

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Originally Posted by matsp

Yes, but D is ON when A or B is ON too, regardless of C.

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Mats

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Hrmz... no luck. The function of D, which is the same as C, still stays on when A and B go off. ugh.. head hurts.. gonna try this again morrow.