Decimal > Binary

[Gemini2008]

i am trying to create a program that will convert binary to decimal, i have got so far:

#include <stdio.h>

main(void)
{
int num1, num2 = 0;

printf("Please enter a value between 0-255: ");
scanf("%d",&num2);

for

(num1=128;num1>0;num1=num1/2);
(num1=64;num1>0;num1=num1/2);
(num1=32;num1>0;num1=num1/2);
(num1=16;num1>0;num1=num1/2);
(num1=8;num1>0;num1=num1/2);
(num1=4;num1>0;num1=num1/2);
(num1=2;num1>0;num1=num1/2);
(num1=1;num1>0;num1=num1/2);
 printf("%d",num1/1);
 num1 = num1 &1;
}

but i keep getting errors and i dont know why, any help would be appreciated.

[tabstop]

Well, the errors tell you what the error is (they're helpful that way). But the upshot is you only get one set of parentheses for a for loop. And the other helpful bit about for loop is you don't have to work out what's going to happen in each loop -- the computer can do that. You just tell it num1 = num1/2 and it can work out that it will go from 128, to 64, to 32, etc.

[blurx]

for

(num1=128;num1>0;num1=num1/2);
(num1=64;num1>0;num1=num1/2);
(num1=32;num1>0;num1=num1/2);
(num1=16;num1>0;num1=num1/2);
(num1=8;num1>0;num1=num1/2);
(num1=4;num1>0;num1=num1/2);
(num1=2;num1>0;num1=num1/2);
(num1=1;num1>0;num1=num1/2);
 printf("%d",num1/1);
 num1 = num1 &1;
}

That translates to:

for(num1 = 128; num1 > 0; num1 /= 2)

I think that's why.