Thread: Is this not the same value?

I have just recently started to learn C. I have been playing around with different code to teach myself. I cannot figure out the following code:

Code:

#include <stdio.h>

void testfunction (int *);

void testfunction2 (int *);

int main (void)
{       
        
        int number = 5, other_number = 5;
        
        testfunction (&number);
        
        printf("\nnumber in main: %d\n\n", number);
        
        testfunction2 (&other_number);
        
        printf("\nother_number in main: %d\n\n", other_number);
        
        return(0);
 
}


void testfunction (int *value)
        
{       
        
        *value++;
        
        printf("\nnumber in testfunction: %d\n", *value);
        
        return;
 
}


void testfunction2 (int *value)

{

        *value += 1;

        printf("\nother_number in testfunction2: %d\n", *value);

        return;

}

For some reason when I run the above program I get this:

Code:

number in testfunction: -1077941616

number in main: 5


other_number in testfunction2: 6

other_number in main: 6

Shouldn't both numbers pointers be 6?

Why am I getting this crazy number? Can I not use "++" outside of a loop? "+=" seems to work just fine.


Thanks for the help!!

Try (*value)++ instead of *value++. (Hooray order of operations.)

yep, that was it.

Thanks!