Thread: how to interprete this signature..

so when it null
we cant access the sub variables

Originally Posted by transgalactic2

but its of a complex type

No. NO. And No. Root is NOT of a complex type. It is a pointer, which is a simple type. ALL it stores is an address. It does not have sub-fields, or anything like that.

Try using root.lc in your code somewhere. Notice how it doesn't work? That's because root is not a struct node. It is a pointer.

thanks i understand this now

Wow... you made tabstop upset. Kudos to you for that.

Originally Posted by Elysia

Updated example. Better now?

Much. Thanks. Its good to see code that is illiterate blond, friendly.

Originally Posted by Elysia

Simple boolean magic.
Basic rules:
0 is false. Always.
Everything else is true. Always.

Basic if form:
if (!tree == true)

Let us assume that tree contains a value of NULL.
Thusly, tree is interpreted as false in boolean form (since NULL is one way or another 0).
Thus, we get:
if (!false == true)

The ! operator will invert the meaning of the value it is applied to, so we get:
if (true == true)

Or in other words, it's a short-hand for:
if (tree == NULL)

so
false=null
and when they say
(!tree) that means tree differs true
so they ask us if tree equals null